000
06.08.2009, 16:13 Uhr
deer
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weiss jemand warum der Ausdruck bei (1) wahr ist? Wenn ich die Pointer (scp und st) ausgebe, haben sie verschiedene Addressen!?
Hier ist der Output:
scp: 0x9b37050, st: 0x9b37040, 0x9b37040
scp==st
übersehe ich was?
Danke!
| C++: |
#include <boost/shared_ptr.hpp>
#include <unordered_map>
#include <string>
#include <stdio.h>
using std::string;
using boost::shared_ptr;
class Symbol {
public:
shared_ptr<Symbol> type;
string name;
Symbol() {}
Symbol(string s, shared_ptr< Symbol > t) : name(s), type(t) {}
virtual ~Symbol() { }
};
typedef std::unordered_map<string, shared_ptr<Symbol>> symMap;
typedef shared_ptr<Symbol> SymPtr;
class Scope {
public:
Scope *parent;
Scope() : parent(0){}
Scope(Scope* p) : parent(p) {}
virtual ~Scope() { }
};
class SymbolWithScope : public Symbol , public Scope{
public:
symMap symbols;
SymbolWithScope() : Symbol(), Scope() {}
SymbolWithScope(Scope* p) : Scope(p) { printf("ctor SymbolWithScope\n"); }
SymbolWithScope(string s, shared_ptr< Symbol > type) : Symbol(s, type) {}
virtual ~SymbolWithScope() { symbols.clear(); }
};
SymbolWithScope start_scope;
Scope *scp = &start_scope;
void foo(SymPtr const& sym)
{
SymbolWithScope *st = dynamic_cast<SymbolWithScope*>(sym.get());
if(st)
{
printf("type is STRUCTSYMBOLSCOPE\n");
printf("scp: %p, st: %p, %p\n", scp, st, sym.get());
if(scp == st)
printf("scp == st\n"); (1)
}
}
int main()
{
printf("----- begin ----- \n");
shared_ptr<SymbolWithScope> scp1(new SymbolWithScope(0));
scp = scp1.get();
foo(scp1);
printf("----- end ----- \n");
}
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